Hi Friend ,
Today I am going to make the single led light flasher circuit by using Bc547.how to make led flasher circuit by using BC 547 in 2022
Led flasher circuit
Let's get started,
Step 1:
Components required
(1) Bc547 transistor×1
(2) 4.7komh ,100ohm resistors×1
(3) 470uf×35vCapacitor×1
(4) Red led
Step 2:
Circuit Diagram
•This is a circuit diagram of the project.
•Connect of all these components according to the circuit diagram of the project.
Step 3:
Connect100(ohm) Resistor
•.Now we have connect the resistor 100(ohm) to the collector pin of the transistor .as show in the picture below.
Step 4:
Connect the led
Now connect the postive (+ve)side of led to the100(ohm,s) resistor and then negative side ( -ve) of led to connect negative terminal of the power supply as show in the picture below
Step 5:
Connect 470uf capacitor
Now we have solder the 470uf×35v capacitor positive (+ve) to connect emitter pin of the transistor and connect negative pin to the GND as show in the picture below.
Step 6:
connect the4.7k(ohm)
Now we have connect the resistor 4.7k(ohm) to the emitter pin of the transistor .as show in the picture below.
Step 7:
connect power supply
Now connect the 12volt positive side( +ve )to the resistor 4.7k and negative side (-ve)to the anode of the led as show in picture below.
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If you have any doutes .Please let me know